v^2+4v+9=-2v

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Solution for v^2+4v+9=-2v equation: 



v^2+4v+9=-2v

We move all terms to the left:

v^2+4v+9-(-2v)=0

We get rid of parentheses

v^2+4v+2v+9=0

We add all the numbers together, and all the variables

v^2+6v+9=0

a = 1; b = 6; c = +9;
Δ = b2-4ac
Δ = 62-4·1·9
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$v=\frac{-b}{2a}=\frac{-6}{2}=-3$

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